Excel求解非线性方程组
- 2026-09-21 13:45:17
Excel求解非线性方程组DeepSeek+Excel VBA,能把问题描述清楚就行: 
已知x0,y0,E,n,K,x*y=x0*y0,x=y/E+2*(y/2/K)^(1/n),在Excel中通过VBA自定义函数求y。
这个问题需要迭代求解,简单说就是不断试算直到误差足够小,力气活,可以在Excel中通过VBA自定义函数solvey秒解y,不需要动用matlab。
Function SolveY(x0 As Double, y0 As Double, E As Double, n As Double, K As Double, Optional initial_guess As Double = -1, Optional max_iter As Integer = 100, Optional tol As Double = 1e-10) As Double' 求解方程: (y/E + 2*(y/(2K))^(1/n)) * y = x0*y0' 使用牛顿迭代法Dim y As DoubleDim f As Double, df As DoubleDim iter As Integer' 初始猜测:如果未提供,用 y0 作为初始值If initial_guess <= 0 Theny = y0Elsey = initial_guessEnd IfFor iter = 1 To max_iter' 计算 f(y) 和 f'(y)f = (y / E + 2 * (y / (2 * K)) ^ (1 / n)) * y - x0 * y0' 导数:d/dy [y^2/E + 2*y*(y/(2K))^(1/n)]df = 2 * y / E + 2 * (y / (2 * K)) ^ (1 / n) + (2 * y / n) * (y / (2 * K)) ^ (1 / n) / y' 避免除零If Abs(df) < 1e-15 ThenSolveY = CVErr(xlErrNA)Exit FunctionEnd If' 牛顿更新y = y - f / df' 检查收敛If Abs(f) < tol ThenExit ForEnd IfNext iterIf iter > max_iter Then' 未收敛SolveY = CVErr(xlErrNA)ElseSolveY = yEnd IfEnd Function

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